Optimal. Leaf size=112 \[ -\frac {a^2 \cot ^5(c+d x)}{5 d}-\frac {i a^2 \cot ^4(c+d x)}{2 d}+\frac {2 a^2 \cot ^3(c+d x)}{3 d}+\frac {i a^2 \cot ^2(c+d x)}{d}-\frac {2 a^2 \cot (c+d x)}{d}+\frac {2 i a^2 \log (\sin (c+d x))}{d}-2 a^2 x \]
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Rubi [A] time = 0.17, antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3542, 3529, 3531, 3475} \[ -\frac {a^2 \cot ^5(c+d x)}{5 d}-\frac {i a^2 \cot ^4(c+d x)}{2 d}+\frac {2 a^2 \cot ^3(c+d x)}{3 d}+\frac {i a^2 \cot ^2(c+d x)}{d}-\frac {2 a^2 \cot (c+d x)}{d}+\frac {2 i a^2 \log (\sin (c+d x))}{d}-2 a^2 x \]
Antiderivative was successfully verified.
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Rule 3475
Rule 3529
Rule 3531
Rule 3542
Rubi steps
\begin {align*} \int \cot ^6(c+d x) (a+i a \tan (c+d x))^2 \, dx &=-\frac {a^2 \cot ^5(c+d x)}{5 d}+\int \cot ^5(c+d x) \left (2 i a^2-2 a^2 \tan (c+d x)\right ) \, dx\\ &=-\frac {i a^2 \cot ^4(c+d x)}{2 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}+\int \cot ^4(c+d x) \left (-2 a^2-2 i a^2 \tan (c+d x)\right ) \, dx\\ &=\frac {2 a^2 \cot ^3(c+d x)}{3 d}-\frac {i a^2 \cot ^4(c+d x)}{2 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}+\int \cot ^3(c+d x) \left (-2 i a^2+2 a^2 \tan (c+d x)\right ) \, dx\\ &=\frac {i a^2 \cot ^2(c+d x)}{d}+\frac {2 a^2 \cot ^3(c+d x)}{3 d}-\frac {i a^2 \cot ^4(c+d x)}{2 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}+\int \cot ^2(c+d x) \left (2 a^2+2 i a^2 \tan (c+d x)\right ) \, dx\\ &=-\frac {2 a^2 \cot (c+d x)}{d}+\frac {i a^2 \cot ^2(c+d x)}{d}+\frac {2 a^2 \cot ^3(c+d x)}{3 d}-\frac {i a^2 \cot ^4(c+d x)}{2 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}+\int \cot (c+d x) \left (2 i a^2-2 a^2 \tan (c+d x)\right ) \, dx\\ &=-2 a^2 x-\frac {2 a^2 \cot (c+d x)}{d}+\frac {i a^2 \cot ^2(c+d x)}{d}+\frac {2 a^2 \cot ^3(c+d x)}{3 d}-\frac {i a^2 \cot ^4(c+d x)}{2 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}+\left (2 i a^2\right ) \int \cot (c+d x) \, dx\\ &=-2 a^2 x-\frac {2 a^2 \cot (c+d x)}{d}+\frac {i a^2 \cot ^2(c+d x)}{d}+\frac {2 a^2 \cot ^3(c+d x)}{3 d}-\frac {i a^2 \cot ^4(c+d x)}{2 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}+\frac {2 i a^2 \log (\sin (c+d x))}{d}\\ \end {align*}
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Mathematica [C] time = 0.81, size = 124, normalized size = 1.11 \[ -\frac {a^2 \cot ^5(c+d x) \, _2F_1\left (-\frac {5}{2},1;-\frac {3}{2};-\tan ^2(c+d x)\right )}{5 d}+\frac {a^2 \cot ^3(c+d x) \, _2F_1\left (-\frac {3}{2},1;-\frac {1}{2};-\tan ^2(c+d x)\right )}{3 d}+\frac {i a^2 \left (-\cot ^4(c+d x)+2 \cot ^2(c+d x)+4 \log (\tan (c+d x))+4 \log (\cos (c+d x))\right )}{2 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.43, size = 218, normalized size = 1.95 \[ \frac {-270 i \, a^{2} e^{\left (8 i \, d x + 8 i \, c\right )} + 600 i \, a^{2} e^{\left (6 i \, d x + 6 i \, c\right )} - 740 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} + 400 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} - 86 i \, a^{2} + {\left (30 i \, a^{2} e^{\left (10 i \, d x + 10 i \, c\right )} - 150 i \, a^{2} e^{\left (8 i \, d x + 8 i \, c\right )} + 300 i \, a^{2} e^{\left (6 i \, d x + 6 i \, c\right )} - 300 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} + 150 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} - 30 i \, a^{2}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} - 1\right )}{15 \, {\left (d e^{\left (10 i \, d x + 10 i \, c\right )} - 5 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 10 \, d e^{\left (6 i \, d x + 6 i \, c\right )} - 10 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 5 \, d e^{\left (2 i \, d x + 2 i \, c\right )} - d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 2.87, size = 212, normalized size = 1.89 \[ \frac {3 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 15 i \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 55 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 180 i \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1920 i \, a^{2} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + i\right ) + 960 i \, a^{2} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 630 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + \frac {-2192 i \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 630 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 180 i \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 55 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 15 i \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 3 \, a^{2}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5}}}{480 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.36, size = 113, normalized size = 1.01 \[ \frac {2 a^{2} \left (\cot ^{3}\left (d x +c \right )\right )}{3 d}-\frac {2 a^{2} \cot \left (d x +c \right )}{d}-2 a^{2} x -\frac {2 a^{2} c}{d}-\frac {i a^{2} \left (\cot ^{4}\left (d x +c \right )\right )}{2 d}+\frac {i a^{2} \left (\cot ^{2}\left (d x +c \right )\right )}{d}+\frac {2 i a^{2} \ln \left (\sin \left (d x +c \right )\right )}{d}-\frac {a^{2} \left (\cot ^{5}\left (d x +c \right )\right )}{5 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.75, size = 109, normalized size = 0.97 \[ -\frac {60 \, {\left (d x + c\right )} a^{2} + 30 i \, a^{2} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) - 60 i \, a^{2} \log \left (\tan \left (d x + c\right )\right ) + \frac {60 \, a^{2} \tan \left (d x + c\right )^{4} - 30 i \, a^{2} \tan \left (d x + c\right )^{3} - 20 \, a^{2} \tan \left (d x + c\right )^{2} + 15 i \, a^{2} \tan \left (d x + c\right ) + 6 \, a^{2}}{\tan \left (d x + c\right )^{5}}}{30 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.16, size = 92, normalized size = 0.82 \[ -\frac {4\,a^2\,\mathrm {atan}\left (2\,\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )}{d}-\frac {2\,a^2\,{\mathrm {tan}\left (c+d\,x\right )}^4-a^2\,{\mathrm {tan}\left (c+d\,x\right )}^3\,1{}\mathrm {i}-\frac {2\,a^2\,{\mathrm {tan}\left (c+d\,x\right )}^2}{3}+\frac {a^2\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}}{2}+\frac {a^2}{5}}{d\,{\mathrm {tan}\left (c+d\,x\right )}^5} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 0.63, size = 218, normalized size = 1.95 \[ \frac {2 i a^{2} \log {\left (e^{2 i d x} - e^{- 2 i c} \right )}}{d} + \frac {- 270 i a^{2} e^{8 i c} e^{8 i d x} + 600 i a^{2} e^{6 i c} e^{6 i d x} - 740 i a^{2} e^{4 i c} e^{4 i d x} + 400 i a^{2} e^{2 i c} e^{2 i d x} - 86 i a^{2}}{15 d e^{10 i c} e^{10 i d x} - 75 d e^{8 i c} e^{8 i d x} + 150 d e^{6 i c} e^{6 i d x} - 150 d e^{4 i c} e^{4 i d x} + 75 d e^{2 i c} e^{2 i d x} - 15 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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